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Marvin sells candy bars at a rate of 3 bars for $4
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26 Mar 2021, 08:07
26 Mar 2021, 08:07
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Question Stats:
54% (00:45) correct
45% (00:37) wrong based on 24 sessions
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Marvin sells candy bars at a rate of 3 bars for $4
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Quantity A |
Quantity B |
at this rate, the cost of x candy bars |
x dollars |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: Marvin sells candy bars at a rate of 3 bars for $4
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26 Mar 2021, 08:24
26 Mar 2021, 08:24
Carcass wrote:
Marvin sells candy bars at a rate of 3 bars for $4
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
at this rate, the cost of x candy bars |
x dollars |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
\(3\) bars for $\(4\) means \(1\) bar for $\(\frac{4}{3}\)
Col. A: \((x)\frac{4}{3} = 1.33x\)
Col. B: \(x\)
Hence, option A
Re: Marvin sells candy bars at a rate of 3 bars for $4
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26 Mar 2021, 14:14
26 Mar 2021, 14:14
If 3 bars cost $4, we can use simple algebra to find that each bar costs 4/3 dollars, or 1.33 collars. Thus the cost of x bars will be 1.33x dollars, which is clearly greater than x dollars.
A is the correct answer.
A is the correct answer.
