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Mary's age is half of Paul's age. In 8 years, Paul will be n years old
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14 Jun 2022, 01:00
14 Jun 2022, 01:00
Expert Reply
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Question Stats:
60% (00:42) correct
40% (02:27) wrong based on 5 sessions
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Mary's age is half of Paul's age. In 8 years, Paul will be n years old. In terms of n, how old is Mary now?
(A) (n/2) - 4
(B) n/2
(C) (n/2) + 4
(D) (n/2) + 8
(E) 2n + 8
(A) (n/2) - 4
(B) n/2
(C) (n/2) + 4
(D) (n/2) + 8
(E) 2n + 8
Part of the project: Skill Builder Project
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GRE Math Essentials
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: Mary's age is half of Paul's age. In 8 years, Paul will be n years old
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14 Jun 2022, 03:19
14 Jun 2022, 03:19
1
In \(8\) years, Paul will be \(n\) years old.
Paul's current age \(= n - 8\)
Mary's age = half of Paul's age
Mary's age \(= \frac{n - 8}{2} = \frac{n}{2} - 4\)
Answer \(A\)
Paul's current age \(= n - 8\)
Mary's age = half of Paul's age
Mary's age \(= \frac{n - 8}{2} = \frac{n}{2} - 4\)
Answer \(A\)
Mary's age is half of Paul's age. In 8 years, Paul will be n years old
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14 Jun 2022, 04:32
14 Jun 2022, 04:32
1
Let P=Paul's age
and M=Mary's age
P=2M
In 8 years, Paul's age will be:
P+8=n
Therefore, Mary's age will then be:
2M+8=n ---> Making M the subject of the equation, \(M=\frac{(n-8)}{2}\)
\(M=\frac{n}{2}-4\)
Answer is (A)
and M=Mary's age
P=2M
In 8 years, Paul's age will be:
P+8=n
Therefore, Mary's age will then be:
2M+8=n ---> Making M the subject of the equation, \(M=\frac{(n-8)}{2}\)
\(M=\frac{n}{2}-4\)
Answer is (A)
