Ratio & Proportions:
Ratios are the way of expressing the relative sizes of two different quantities. Ratios are expressed as, x:y or \(\frac{x}{y}\). Like fractions, even ratios can be expressed in the form of their reduced equivalent forms. Meaning, 2:3 is same as 4:6.
A proportion is an equation relating two different ratios as, a:b = c:d. If a proportion is in the form of a:b = b:c. Then it is called to be in continuous proportion. We cross multiply the fractions to solve proportions.
Rules of Ratio:
Ratios have some basic rules to solve which are,
If \(\frac{a}{b} = \frac{c}{d} = \frac{e}{f}\), then \(\frac{{a+c+e}}{{b+d+f}}\). This is termed as property of equal ratios. Keep in mind, this holds true for any number of equal ratios.
If \(\frac{a}{b} = \frac{c}{d}\), then \(\frac{{a+b}}{{a-b}} = \frac{{c+d}}{{c-d}}\). This is termed as componendo and dividendo.
If \(\frac{a}{b} = \frac{c}{d} = \frac{e}{f}\), then a:c:e = b:d:f.
Useful Tricks
When a question is asked to find A:B:C:D, given that A:B = m:n, B:C = o:p and C:D = q:r. We have a simple trick to solve this kind of question which can save time during exams. This is explained in the following picture.
![Image](https://gre.myprepclub.com/forum/download/file.php?id=409)
In case of only three variables, it is solved as,
![Image](https://gre.myprepclub.com/forum/download/file.php?id=409)
If a question is asked such that, a container contains a mixture of oil and water in ratio M:N, with the total amount of liquid, is x litres. What amount of water to be so that the ration becomes A:B?
In this case use the following formula,
\(\frac{x(MB-NA)}{A(M+N)}\)
For example,
A tank consists of a mixture of milk and water in ratio 2:3. The total amount of mixture is 10 litres. How much water should be added, so that the ratio becomes 1:3?
Using the above formula, the amount of water to be added = \(\frac{10(2*3 - 3*1)}{1(2+3)} = \frac{6}{1}\) litres