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N=87^56 and P=93^43
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17 Jul 2024, 00:56
17 Jul 2024, 00:56
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Question Stats:
88% (01:33) correct
11% (01:09) wrong based on 18 sessions
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\(N=87^{56}\) and \(P=93^{43}\)
Quantity A |
Quantity B |
Digit at unit place of \(N+P\) |
Digit at unit place of \(N \times P\) |
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Shorter GRE - Preparing for the Quantitative Reasoning Measure
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Free Materials for the GRE General Exam - Where to get it!!
Shorter GRE - Preparing for the Quantitative Reasoning Measure
Shorter GRE - Preparing for the Verbal Reasoning Measure
Re: N=87^56 and P=93^43
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22 Sep 2024, 18:34
22 Sep 2024, 18:34
1
The cycle of unit digits of 7 is 7, 9, 3, 1 (7^1 = 7, 7^2 = 49, 7^3 = 343, 7^4 = 2401, 7^5 = 16807 and so on)
The cycle of unit digits of 3 is 3, 9, 7, 1 (3^1 = 3, 3^2 = 9, 3^3 = 27, 3^4 = 81, 3^5 = 243 and so on)
56 is divisible by 4 so unit digit of 87^56 is 1
43 divides by 4 has remainder 3, so unit digit of of 93^43 is 7
A = 1 + 7 = 8 > B = 1 * 7 = 7
=> A
The cycle of unit digits of 3 is 3, 9, 7, 1 (3^1 = 3, 3^2 = 9, 3^3 = 27, 3^4 = 81, 3^5 = 243 and so on)
56 is divisible by 4 so unit digit of 87^56 is 1
43 divides by 4 has remainder 3, so unit digit of of 93^43 is 7
A = 1 + 7 = 8 > B = 1 * 7 = 7
=> A
gmatclubot
Re: N=87^56 and P=93^43 [#permalink]
22 Sep 2024, 18:34
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