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N is a positive integer that is divisible by both 6 and 10.
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12 Jul 2023, 01:03
12 Jul 2023, 01:03
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20% (00:16) wrong based on 10 sessions
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N is a positive integer that is divisible by both 6 and 10.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
_________________
Quantity A |
Quantity B |
Remainder when N is divided by 30 |
Remainder when N is divided by 60 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
_________________
Re: N is a positive integer that is divisible by both 6 and 10.
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14 Jul 2023, 12:46
14 Jul 2023, 12:46
1
LCM of 6 and 10 would be the first number which would be divisible by both 6 and 10
LCM is 30.
All the multiples of 30 would also satisfy the problem.
Case 1: considering 30 as N then A would result in 0 as remainder of 30/30 is 0
For B, remainder of 30/60 would result in 30
Therefore, A<B
Case 2: Considering 60 (a multiple of 30) as N
A: 0 (remainder of 60/30=0)
B: 0 (remainder of 60/60=0)
Therefore A = B
Correct Option D.
LCM is 30.
All the multiples of 30 would also satisfy the problem.
Case 1: considering 30 as N then A would result in 0 as remainder of 30/30 is 0
For B, remainder of 30/60 would result in 30
Therefore, A<B
Case 2: Considering 60 (a multiple of 30) as N
A: 0 (remainder of 60/30=0)
B: 0 (remainder of 60/60=0)
Therefore A = B
Correct Option D.
gmatclubot
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