We know $\(N\)$ is a positive integer; we need to compare the remainder when $\(\left(N^2-N\right)\)$ is divided by 2 with 0 .

The given expression $\(\left(\mathrm{N}^2-\mathrm{N}\right)=\mathrm{N}(\mathrm{N}-1)\)$ is a product of two consecutive positive integers, which must be divisible by 2 . So, the remainder when $\(\left(N^2-N\right)\)$ is divided by 2 must be 0 .


(Note: - Product of n consecutive positive integers is divisible by $\(n!\)$ )

Hence column A quantity equals column B quantity, so the answer is (C).