OE


As 𝑁 is the product of 5 consecutive prime numbers, and 𝑁 is also divisible by 10,
thus 𝑁 will definitely include 2 and 5
Therefore, only 5 consecutive integers will be 2, 3, 5,7, 11.
→ 𝑁 = 2 × 3 × 5 × 7 × 11
Thus, among the options, the number which can completely divide 𝑁 will be the
divisor of 𝑁. Hence; the following will definitely be the divisors of 𝑁;

2, 6, 14, 22, 30
Ans. (A, B, D, E, F)
_________________

Given that N is the product of 5 consecutive primes and N is a multiple of 10 (5x2). Hence, N will definitely include 2 & 5.
Since N will include 2 (smallest prime), ideally N should be equal to 2 x 3 x 5 x 7 x 11.

Therefore, the following amongst the options must be a divisor:
A) 2,
B) 6 (2 x 3)
D) 14 (2 x 7)
E) 22 (2 x 11)
F) 30 (2 x 3 x 5)