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Neel and Jacob start from opposite ends of a 28-mile trail and begin h
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26 Apr 2022, 01:15
26 Apr 2022, 01:15
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80% (01:22) correct
20% (01:17) wrong based on 10 sessions
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Neel and Jacob start from opposite ends of a 28-mile trail and begin hiking toward each other at the same time. If Neel hikes at a constant 4 miles per hour and Jacob hikes at a constant 3 miles per hour, how many miles will Neel have traveled when he meets Jacob?
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16
Part of the project: GRE Quantitative Reasoning Daily Challenge - (2022) EDITION
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
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Re: Neel and Jacob start from opposite ends of a 28-mile trail and begin h
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26 Apr 2022, 07:06
26 Apr 2022, 07:06
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Carcass wrote:
Neel and Jacob start from opposite ends of a 28-mile trail and begin hiking toward each other at the same time. If Neel hikes at a constant 4 miles per hour and Jacob hikes at a constant 3 miles per hour, how many miles will Neel have traveled when he meets Jacob?
Show: ::
16
Let's start by writing a word equation.
When the two travelers meet, they will have both hiked for the same amount of time.
So, we can write: Neel's travel time = Jacob's travel time
Let d = the number of miles Neel traveled
So, 28 - d = the number of miles Jacob traveled (since the sum of their distances must be 28)
Time = distance/rate, so we can plug our values into the word equation to get: d/4 = (28 - d)/3
Multiply both sides of the equation by 12 to get: 3d = 112 - 4d
Add 4d to both sides: 7d = 112
Solve: d = 112/7 = 16
Answer: 16
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Joined: 11 Sep 2023
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GRE 1: Q155 V141
Re: Neel and Jacob start from opposite ends of a 28-mile trail and begin h
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10 Oct 2023, 01:15
10 Oct 2023, 01:15
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When two objects travel towards each other, their travelling speed gets added.
Hence, in above case, speed becomes, 4+3=7miles/h
Now, the distance is given as 28 miles.
hence the time when they meet = distance/combined speed = 28/7 = 4h
Hence in 4 hours, need would have covered 4*4 distance.
That's why answer is 16.
Hence, in above case, speed becomes, 4+3=7miles/h
Now, the distance is given as 28 miles.
hence the time when they meet = distance/combined speed = 28/7 = 4h
Hence in 4 hours, need would have covered 4*4 distance.
That's why answer is 16.
