GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
O is the center of the circle with radius r
[#permalink]
05 May 2021, 01:53
05 May 2021, 01:53
Expert Reply
4
Bookmarks
00:00
Question Stats:
74% (01:37) correct
25% (01:44) wrong based on 43 sessions
Hide Show timer Statistics
Attachment:
GRE O is the center of the circle with radius r.jpg [ 14.19 KiB | Viewed 2834 times ]
O is the center of the circle of radius r
Quantity A |
Quantity B |
\(OP\) |
\(\frac{r}{\sqrt{2}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
O is the center of the circle with radius r
[#permalink]
05 May 2021, 10:36
05 May 2021, 10:36
1
Carcass wrote:
Attachment:
GRE O is the center of the circle with radius r.jpg
O is the center of the circle of radius r
Quantity A |
Quantity B |
\(OP\) |
\(\frac{r}{\sqrt{2}}\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
OP is perpendicular bisector of a right isosceles triangle with two sides as \(r\) and the hypotenuse as \(\sqrt{2}r\)
OP bisects the base into two equal parts i.e. \(\frac{r}{\sqrt{2}}\)
Apply Pythagoras theorem to find the length of OP:
\(r^2 = (\frac{r}{\sqrt{2}})^2 + OP^2\)
\(OP = \frac{r}{\sqrt{2}}\)
Clearly, Col. A = Col. B
Hence, option C
Re: O is the center of the circle with radius r
[#permalink]
13 Oct 2025, 01:06
13 Oct 2025, 01:06
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
