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Re: O is the circle’s center and ∠POR is a right angle.
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03 Feb 2019, 20:27
The answer is wrong but the concept is correct Opposite angles are equal so <POQ = 43 <QOR = 90 - 43 = 47 Also <OQR = 180 - (90+47) = 43 Hence, from the scenario opposite side of the greater angle has greatest length QR > OR The answer is B
Re: O is the circle’s center and ∠POR is a right angle.
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03 Feb 2019, 23:06
Expert Reply
amorphous wrote:
Attachment:
The attachment circle dotted.png is no longer available
O is the circle’s center and ∠POR is a right angle.
Quantity A
Quantity B
OR
QR
Quantity A is greater. Quantity B is greater. The two quantities are equal. The relationship cannot be determined from the information given.
See the attached figure..
Rule : Side opposite larger angle with in the same triangle is larger than the side opposite smaller angles.
Take triangle OQR, which is a right angled triangle.. angle QOR = 180-(angle TOS + angle SOR)=180-(43+90)=47. angle OQR=180-(90+angle QOR)=180-(90+47)=43. thus angle QOR>angle OQR, therefore (side opposite angle QOR)>(side opposite angle OQR).. or QR>OR, that is B>A
B
Attachments
circle dotted.png [ 5.38 KiB | Viewed 5266 times ]
Re: O is the circles center and POR is a right angle.
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10 Jun 2023, 07:47
Hello from the GRE Prep Club BumpBot!
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