Last visit was: 18 Jul 2024, 09:15 It is currently 18 Jul 2024, 09:15

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 29118
Own Kudos [?]: 34135 [11]
Given Kudos: 25509
Send PM
Most Helpful Community Reply
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11874 [12]
Given Kudos: 136
Send PM
General Discussion
Manager
Manager
Joined: 06 Jun 2018
Posts: 102
Own Kudos [?]: 121 [0]
Given Kudos: 4
Send PM
avatar
Manager
Manager
Joined: 02 Mar 2020
Posts: 54
Own Kudos [?]: 14 [0]
Given Kudos: 0
Send PM
Re: p + |k| > |p| + k [#permalink]
Can someone explain some more?
avatar
Intern
Intern
Joined: 18 Apr 2020
Posts: 14
Own Kudos [?]: 29 [4]
Given Kudos: 0
Send PM
Re: p + |k| > |p| + k [#permalink]
4
another way could be to square both sides of the inequality

you would be left with P|K| > |P|K.....this can only be true when P>K.....

Therefore A..

Cheers.
Senior Manager
Senior Manager
Joined: 23 Jan 2021
Posts: 294
Own Kudos [?]: 155 [1]
Given Kudos: 81
Concentration: , International Business
Send PM
Re: p + |k| > |p| + k [#permalink]
1
sumit0503 wrote:
another way could be to square both sides of the inequality

you would be left with P|K| > |P|K.....this can only be true when P>K.....

Therefore A..

Cheers.

CAn you please explain in detail?
Intern
Intern
Joined: 20 Mar 2021
Posts: 17
Own Kudos [?]: 12 [5]
Given Kudos: 0
Send PM
Re: p + |k| > |p| + k [#permalink]
3
2
Bookmarks
p+ |k| > |p|+k
squaring both sides and cancelling equal terms
p*|k| > |p|*k ----- our equation
|k| positive
|p| positive

Above inequality will only be possible if k is negative
How?
if k=1
p>|p| not possible
so p has to be positive ---- First conclusion

if k=-1 and p is greater than k say p=2 or p=1
p*|k| > negative
then our equation becomes true
So p > k
avatar
Intern
Intern
Joined: 06 Jun 2022
Posts: 1
Own Kudos [?]: 1 [1]
Given Kudos: 0
Send PM
Re: p + |k| > |p| + k [#permalink]
1
I want to go back to school but I'm dreading the GRE. I'm at work so I thought I'd start looking at some questions to familiarize myself with the math. (I'm fine with the verbal part, but math kills me.)

This was the first question I saw, and I officially give up. :cry:
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 11874 [1]
Given Kudos: 136
Send PM
Re: p + |k| > |p| + k [#permalink]
1
ATT123 wrote:
I want to go back to school but I'm dreading the GRE. I'm at work so I thought I'd start looking at some questions to familiarize myself with the math. (I'm fine with the verbal part, but math kills me.)

This was the first question I saw, and I officially give up. :cry:

Don't give up. This is a pretty tricky question.
To get a better idea of what to expect on test day, use GRE Prep Club's filter to isolate official GRE questions
Verbal Expert
Joined: 18 Apr 2015
Posts: 29118
Own Kudos [?]: 34135 [0]
Given Kudos: 25509
Send PM
Re: p + |k| > |p| + k [#permalink]
Expert Reply
ATT123 wrote:
I want to go back to school but I'm dreading the GRE. I'm at work so I thought I'd start looking at some questions to familiarize myself with the math. (I'm fine with the verbal part, but math kills me.)

This was the first question I saw, and I officially give up. :cry:


As GreenlightTestPrep pointed out: there is NOTHING , whatsoever, to give up.

Instead the GRE is the moment to double down and face the challenge.

It is just a test. Life could be tough. The GRE is just a test
Retired Moderator
Joined: 28 Sep 2020
Posts: 136
Own Kudos [?]: 114 [1]
Given Kudos: 2
Send PM
Re: p + |k| > |p| + k [#permalink]
1
Given, p+|k|>|p|+k

and knowing the absolute value of a negative/positive number has got to give us a positive outcome, then logically P has got to be greater than K, otherwise the left side of the equality would yeild to K dominating P in case it is in negative form.

It might be easier to try a couple scenarios such as P=-1 and k=-2, if we reverse the values making k greater, then equality is not valid.

Answer is (A)
avatar
Intern
Intern
Joined: 20 Jun 2024
Posts: 1
Own Kudos [?]: 1 [1]
Given Kudos: 0
Send PM
Re: p + |k| > |p| + k [#permalink]
1
I don't know if this is correct. But can't you just subtract |p| + |k| from both sides and get
p - |p| > k - |k|

Then it would follow that p > k

because if P is positive,
0 > k - |k| would imply k is negative because it can't be equal
0 > 2k
p > k

because if P is negative,
negative > k -|k| would imply k is negative again

and in the case of negatives, it is akin to saying
2p > 2k
p > k
Prep Club for GRE Bot
[#permalink]
Moderators:
GRE Instructor
48 posts
GRE Forum Moderator
25 posts
Moderator
1091 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne