Approach #1: Probability rules
P(both heads) = P(1st toss is heads AND 2nd toss is heads)
= P(1st toss is heads) x P(2nd toss is heads)
= 1/2 x 1/2
= 1/4
Answer: B

Approach #2: Counting
P(both heads) = (# of outcomes in which both tosses are heads)/(total # of possible outcomes)

Since there are so few outcomes, let's just list them:
- 1st toss is heads and 2nd toss is heads
- 1st toss is heads and 2nd toss is tails
- 1st toss is tails and 2nd toss is heads
- 1st toss is tails and 2nd toss is tails
total # of possible outcomes = 4

Among those 4 possible outcomes, only 1 outcome meets the condition that both tosses are heads

So, P(both heads) = 1/4
Answer: B

Cheers,
Brent