Re: Which of the following numbers are divisible by 6 but not by 18? Indi
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06 Oct 2022, 17:10
First we check if the numbers a re divisible by 6. The rule says the addition of the digits should be divisible by 3 and by 2
a) 1+2+9+6 = 18
b) 2+7+4+4 = 17 not divisible by 6
c) 3+0+7+2 = 12
d) 4+3+5+6 = 18
e) 5+8+3+2 = 18
f) 6+0+0+0 = 6
g) 7+2+9+0 = 18
h) 3+1+1+2 = 7 not divisible by 6
Now we are left with the following numbers. To find if they are divisible by 18, the divisibility rule says it should be divisible by 2 (all of them are even in this case) and the should be divisible by 9. The sum of the digits should be divisible by 9
a) 1+2+9+6 = 18 divisible by 9
c) 3+0+7+2 = 12 NOT divisible by 9
d) 4+3+5+6 = 18 divisible by 9
e) 5+8+3+2 = 18 divisible by 9
f) 6+0+0+0 = 6 NOT divisible by 9
g) 7+2+9+0 = 18 divisible by 9
Answer should be C and F