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The lenghts of two sides of a triangle are 7 and 11
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Updated on: 09 Jul 2017, 00:55
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Question Stats:
77% (00:23) correct
22% (00:13) wrong based on 35 sessions
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Hi guys! So, this is the second time I face this type of problem involving the sides of a triangle. Here is type of comparison question:
The lengths of two sides of a triangle are 7 and 11
Quantity A
Quantity B
The length of the third side
4
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
My first thought was to use Pythagoras theorem and them I would find either 6√2 (considering 11 the largest side) or √170 (considering this new side the largest side). I would like to know what do you guys think about this approach and if you guys would use another way to solve it.
Re: Triangle Problem
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08 Jul 2017, 14:10
2
MateusLima30 wrote:
Hi guys! So, this is the second time I face this type of problem involving the sides of a triangle. Here is type of comparison question:
"The lenghts of two sides of a triangle are 7 and 11."
Quantity A --> The lenght of the third side Quantity B --> 4
My first thought was to use Pitagoras theorem and them I would find either 6√2 (considering 11 the largest side) or √170 (considering this new side the largest side). I would like to know what do you guys think about this approach and if you guys would use another way to solve it.
Thank!
IMPORTANT RULE: If two sides of a triangle have lengths A and B, then . . . DIFFERENCE between A and B < length of third side < SUM of A and B
So, for this question, we get: 11 - 7 < third side < 11 + 7 In other words: 4 < third side < 11
Since the 3rd side must be greater than 4, the correct answer is A
Re: Triangle Problem
[#permalink]
15 Aug 2020, 19:50
GreenlightTestPrep wrote:
MateusLima30 wrote:
Hi guys! So, this is the second time I face this type of problem involving the sides of a triangle. Here is type of comparison question:
"The lenghts of two sides of a triangle are 7 and 11."
Quantity A --> The lenght of the third side Quantity B --> 4
My first thought was to use Pitagoras theorem and them I would find either 6√2 (considering 11 the largest side) or √170 (considering this new side the largest side). I would like to know what do you guys think about this approach and if you guys would use another way to solve it.
Thank!
IMPORTANT RULE: If two sides of a triangle have lengths A and B, then . . . DIFFERENCE between A and B < length of third side < SUM of A and B
So, for this question, we get: 11 - 7 < third side < 11 + 7 In other words: 4 < third side < 11
Since the 3rd side must be greater than 4, the correct answer is A
Re: The lenghts of two sides of a triangle are 7 and 11
[#permalink]
18 Aug 2020, 12:52
1
The minimum possible value for the 3rd side is 5, since, for a given triangle the sum of any two sides > third side, if we consider the third side = 4, then 7+4 is not greater than 11. If this side = 3, 7+3 is again not greater than 11. Hence, the minimum possible value for the third side is 5.
gmatclubot
Re: The lenghts of two sides of a triangle are 7 and 11 [#permalink]