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Re: The lenghts of two sides of a triangle are 7 and 11 [#permalink]
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Please read this link qq-how-to-post-a-gre-question-the-easy-way-2357.html on how to proper post a question

Thank you so much.
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Re: The lenghts of two sides of a triangle are 7 and 11 [#permalink]
Hey there is a triangle rule of sides which is difference of two side < third side < sum of the other two side
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Re: Triangle Problem [#permalink]
GreenlightTestPrep wrote:
MateusLima30 wrote:
Hi guys! So, this is the second time I face this type of problem involving the sides of a triangle. Here is type of comparison question:

"The lenghts of two sides of a triangle are 7 and 11."

Quantity A --> The lenght of the third side
Quantity B --> 4

My first thought was to use Pitagoras theorem and them I would find either 6√2 (considering 11 the largest side) or √170 (considering this new side the largest side). I would like to know what do you guys think about this approach and if you guys would use another way to solve it.

Thank!


IMPORTANT RULE: If two sides of a triangle have lengths A and B, then . . .
DIFFERENCE between A and B < length of third side < SUM of A and B

So, for this question, we get: 11 - 7 < third side < 11 + 7
In other words: 4 < third side < 11

Since the 3rd side must be greater than 4, the correct answer is A

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You mean third side less than 18
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Re: The lenghts of two sides of a triangle are 7 and 11 [#permalink]
1
The minimum possible value for the 3rd side is 5,
since, for a given triangle the sum of any two sides > third side, if we consider the third side = 4, then 7+4 is not greater than 11. If this side = 3, 7+3 is again not greater than 11. Hence, the minimum possible value for the third side is 5.
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Re: The lenghts of two sides of a triangle are 7 and 11 [#permalink]
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