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Set A={9, 13, 4, 2, 7} Set B={9, 13, 4, 2, 9} Set C={9, 13, 4, 2, 4}
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14 Nov 2022, 07:55
14 Nov 2022, 07:55
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80% (02:20) wrong based on 15 sessions
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Set A={9, 13, 4, 2, 7}
Set B={9, 13, 4, 2, 9}
Set C={9, 13, 4, 2, 4}
Set D={9, 13, 4, 2, 6}
Which of the following statement illustrates the exact order of standard deviation of these sets of numbers from the lowest to the greatest?
A. A < B < C < D
B. A < B < D < C
C. D < B < C < A
D. C < B < D < A
E. A < D < B < C
Set B={9, 13, 4, 2, 9}
Set C={9, 13, 4, 2, 4}
Set D={9, 13, 4, 2, 6}
Which of the following statement illustrates the exact order of standard deviation of these sets of numbers from the lowest to the greatest?
A. A < B < C < D
B. A < B < D < C
C. D < B < C < A
D. C < B < D < A
E. A < D < B < C
Re: Set A={9, 13, 4, 2, 7} Set B={9, 13, 4, 2, 9} Set C={9, 13, 4, 2, 4}
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14 Nov 2022, 08:55
14 Nov 2022, 08:55
1
In order to solve this problem, I found the mean of each set and then took the absolute value of the variances of each value in the set in relation to the mean. Then I added them all together to give me an estimate of the standard deviation. That looked something like this:
Set A mean = 7 —> 2, 6, 5, 0 ==> 13
Set B mean = 7.4 —> 1.6, 5.6, 3.4, 5.4, 1.6 = 17.6
Set C mean = 6.4 —> 2.6 , 6.6, 2.4, 4.4, 2.4 = 18.4
Set D mean = 6.8 —> 2.2 , 6.2 , 2.8 , 4.8 , 0.8 = 16.8
13 < 16.8 < 17.6 < 18.4
A < D < B < C ------> Answer Choice E
Set A mean = 7 —> 2, 6, 5, 0 ==> 13
Set B mean = 7.4 —> 1.6, 5.6, 3.4, 5.4, 1.6 = 17.6
Set C mean = 6.4 —> 2.6 , 6.6, 2.4, 4.4, 2.4 = 18.4
Set D mean = 6.8 —> 2.2 , 6.2 , 2.8 , 4.8 , 0.8 = 16.8
13 < 16.8 < 17.6 < 18.4
A < D < B < C ------> Answer Choice E
Re: Set A={9, 13, 4, 2, 7} Set B={9, 13, 4, 2, 9} Set C={9, 13, 4, 2, 4}
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14 Nov 2022, 19:09
14 Nov 2022, 19:09
r1smith wrote:
In order to solve this problem, I found the mean of each set and then took the absolute value of the variances of each value in the set in relation to the mean. Then I added them all together to give me an estimate of the standard deviation. That looked something like this:
Set A mean = 7 —> 2, 6, 5, 0 ==> 13
Set B mean = 7.4 —> 1.6, 5.6, 3.4, 5.4, 1.6 = 17.6
Set C mean = 6.4 —> 2.6 , 6.6, 2.4, 4.4, 2.4 = 18.4
Set D mean = 6.8 —> 2.2 , 6.2 , 2.8 , 4.8 , 0.8 = 16.8
13 < 16.8 < 17.6 < 18.4
A < D < B < C ------> Answer Choice E
Set A mean = 7 —> 2, 6, 5, 0 ==> 13
Set B mean = 7.4 —> 1.6, 5.6, 3.4, 5.4, 1.6 = 17.6
Set C mean = 6.4 —> 2.6 , 6.6, 2.4, 4.4, 2.4 = 18.4
Set D mean = 6.8 —> 2.2 , 6.2 , 2.8 , 4.8 , 0.8 = 16.8
13 < 16.8 < 17.6 < 18.4
A < D < B < C ------> Answer Choice E
This is a standard approach that everyone would follow. I was hoping for something like estimation or any simplified methods.
