Last visit was: 22 Dec 2024, 12:01 It is currently 22 Dec 2024, 12:01

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30461
Own Kudos [?]: 36818 [18]
Given Kudos: 26100
Send PM
Most Helpful Community Reply
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12234 [9]
Given Kudos: 136
Send PM
General Discussion
avatar
Intern
Intern
Joined: 17 Jul 2017
Posts: 15
Own Kudos [?]: 10 [0]
Given Kudos: 0
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30461
Own Kudos [?]: 36818 [0]
Given Kudos: 26100
Send PM
Re: If a – b = 16 and [#permalink]
Expert Reply
greprepclub-the-questions-vault-3523.html#p7347

More questions on their way

Regards
avatar
Intern
Intern
Joined: 23 Nov 2017
Posts: 45
Own Kudos [?]: 87 [4]
Given Kudos: 0
Send PM
Re: If a – b = 16 and [#permalink]
4
I am posting my answer to exemplify how important it is to make sure you are taking the shortest possible route when solving a problem. I didn't do that and look at the monster I got when I tried to use substitution:

A - B = 16
A = 16 + B

Now I substituted the A for 16 + B in the other equation:

√A + √B) = 8
√(16 + B) + √B = 8

√(16 + B) = 8 - √B

Both sides are squared trying to get rid of the square root:

(√(16 + B))^2 = (8 - √B)^2
16 + B = (8 - √B) x (8 - √B)
16 + B = 64 -16√B + B
-64 -B -64 -B
-48 = -16√B

Square both sides again to get rid of the radical:

(-48)^2 = (-16√B)^2
2304 = 256B
B = 2304/256
B = 9

Now substitute the B in the first equation:

A - B = 16
A - 9 = 16
A = 25

Now plug in A and B in the third equation:

√AB = ?
√(9) x (25)
√225
= 15

Sorry it is a little confusing. This is my first post. I am a little pround I got the final result after this mathmatical ordeal.
avatar
Intern
Intern
Joined: 27 Oct 2018
Posts: 49
Own Kudos [?]: 37 [0]
Given Kudos: 0
Send PM
Re: If a – b = 16 and [#permalink]
1
Once you hit the right road, its real easy.

a - b = (root(a) + root(b)) (root(a) - root(b))
avatar
Intern
Intern
Joined: 10 Sep 2018
Posts: 2
Own Kudos [?]: 0 [0]
Given Kudos: 0
Send PM
Re: If a – b = 16 and [#permalink]
Why can't we take square root of (root(a) +root(b))^2 = 8^2 and then solve for root(ab)?
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12234 [0]
Given Kudos: 136
Send PM
Re: If a – b = 16 and [#permalink]
2
mibad wrote:
Why can't we take square root of (root(a) +root(b))^2 = 8^2 and then solve for root(ab)?


Can you show us what you mean?

Cheers,
Brent
avatar
Intern
Intern
Joined: 10 Sep 2018
Posts: 2
Own Kudos [?]: 0 [0]
Given Kudos: 0
Send PM
Re: If a – b = 16 and [#permalink]
roota+rootb = 8
(roota+rootb)^2=8^2
a+2root(a)*root(b)+b=64
2root(ab)=64-a-b

a-b=16

2root(ab)=64-16
root(ab)=48/2
root(ab)=24
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12234 [0]
Given Kudos: 136
Send PM
Re: If a – b = 16 and [#permalink]
1
mibad wrote:
roota+rootb = 8
(roota+rootb)^2=8^2
a + 2(√a)(√b) + b = 64
2√(ab) = 64 - a - b

a - b = 16

2√(ab) = 64 - 16

√(ab) = 48/2
√(ab) = 24


I've highlighted a problem above.
In short, 64 - a - b is NOT the same as 64 - (a - b)


You're correct to say that: 2√(ab) = 64 - a - b
We can rewrite the right side as: 2√(ab) = 64 - (a + b)
The problem is that we don't know the value of a+b.

Does that help?

Cheers,
Brent
avatar
Manager
Manager
Joined: 18 Jun 2019
Posts: 122
Own Kudos [?]: 42 [0]
Given Kudos: 0
Send PM
Re: If a – b = 16 and [#permalink]
mibad wrote:
roota+rootb = 8
(roota+rootb)^2=8^2
a+2root(a)*root(b)+b=64
2root(ab)=64-a-b

a-b=16

2root(ab)=64-16
root(ab)=48/2
root(ab)=24



this is what i did too...
avatar
Manager
Manager
Joined: 04 Apr 2020
Posts: 90
Own Kudos [?]: 83 [2]
Given Kudos: 0
Send PM
Re: If a – b = 16 and [#permalink]
2
I don't know if I was extremely lucky or it was intuition.

I looked at root(a) + root(b) = 8 and the a - b = 16 equations, and also the options. All are integers, no points or fractions or roots in the values. So I figured a and b have to be integers.

root(a) + root(b) = 8
This means that the roots of a and b are less than 8 because roots cannot be negative.

The first option that popped in my mind was 5 + 3 = 8. So I plugged them in the other equation and found that indeed, 25 - 9 = 16.

So root(ab) = root(a)*root(b) = 3*5 = 15.
Intern
Intern
Joined: 26 Dec 2023
Posts: 44
Own Kudos [?]: 16 [0]
Given Kudos: 4
Send PM
If a b = 16 and [#permalink]
I did this the way Zohair did this, but thought in less math and more words if that's helpful. So writing the same thing, but with less math terms.

I guessed sqrt(a) and sqrt(b) were probably integers, based on there only being integers in the question and answers. So I tried to guess which perfect squares subtract to get 16. Probably smallish since their sqrts add to 8. I guessed 5 and 3 as the sqrts, since those add to 8, and lo and behold, 25 and 9 subtract to get 16.

So a and b are 25 and 9, and just go from there. 25*9 = 225, sqrt of which is 15.
Prep Club for GRE Bot
If a b = 16 and [#permalink]
Moderators:
GRE Instructor
88 posts
GRE Forum Moderator
37 posts
Moderator
1115 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne