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If a – b = 16 and √a+√b=8 , what is the value √ab ?
(A) 2 (B) 4 (C) 8 (D) 12 (E) 15
IMPORTANT: (√a + √b)(√a - √b) = a - b [this is a cute version of difference of squares] We're told that a - b = 16 AND √a + √b = 8 Plug these values into the equation to get: (8)(√a - √b) = 16 From this, we can see that √a - √b = 2
We have: √a + √b = 8 √a - √b = 2
When we ADD the two equations, we get: 2√a = 10, which means √a = 5 When we SUBTRACT the bottom equation from the top, we get: 2√b = 6, which means √b = 3
Re: If a – b = 16 and
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23 Nov 2017, 22:59
4
I am posting my answer to exemplify how important it is to make sure you are taking the shortest possible route when solving a problem. I didn't do that and look at the monster I got when I tried to use substitution:
A - B = 16 A = 16 + B
Now I substituted the A for 16 + B in the other equation:
√A + √B) = 8 √(16 + B) + √B = 8
√(16 + B) = 8 - √B
Both sides are squared trying to get rid of the square root:
(√(16 + B))^2 = (8 - √B)^2 16 + B = (8 - √B) x (8 - √B) 16 + B = 64 -16√B + B -64 -B -64 -B -48 = -16√B
Square both sides again to get rid of the radical:
(-48)^2 = (-16√B)^2 2304 = 256B B = 2304/256 B = 9
Now substitute the B in the first equation:
A - B = 16 A - 9 = 16 A = 25
Now plug in A and B in the third equation:
√AB = ? √(9) x (25) √225 = 15
Sorry it is a little confusing. This is my first post. I am a little pround I got the final result after this mathmatical ordeal.
Re: If a – b = 16 and
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17 Jul 2019, 10:15
1
mibad wrote:
roota+rootb = 8 (roota+rootb)^2=8^2 a + 2(√a)(√b) + b = 64 2√(ab) = 64 - a - b
a - b = 16
2√(ab) = 64 - 16 √(ab) = 48/2 √(ab) = 24
I've highlighted a problem above. In short, 64 - a - b is NOT the same as 64 - (a - b)
You're correct to say that: 2√(ab) = 64 - a - b We can rewrite the right side as: 2√(ab) = 64 - (a + b) The problem is that we don't know the value of a+b.
Re: If a – b = 16 and
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02 May 2020, 03:31
2
I don't know if I was extremely lucky or it was intuition.
I looked at root(a) + root(b) = 8 and the a - b = 16 equations, and also the options. All are integers, no points or fractions or roots in the values. So I figured a and b have to be integers.
root(a) + root(b) = 8 This means that the roots of a and b are less than 8 because roots cannot be negative.
The first option that popped in my mind was 5 + 3 = 8. So I plugged them in the other equation and found that indeed, 25 - 9 = 16.
I did this the way Zohair did this, but thought in less math and more words if that's helpful. So writing the same thing, but with less math terms.
I guessed sqrt(a) and sqrt(b) were probably integers, based on there only being integers in the question and answers. So I tried to guess which perfect squares subtract to get 16. Probably smallish since their sqrts add to 8. I guessed 5 and 3 as the sqrts, since those add to 8, and lo and behold, 25 and 9 subtract to get 16.
So a and b are 25 and 9, and just go from there. 25*9 = 225, sqrt of which is 15.
Re: If a b = 16 and
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05 Mar 2025, 12:20
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