rubytuesdays21 wrote:
It's important to note that we know it is divisible by 3 because (a-1)(a)(a+1) represents three consecutive integers. Since the question states it is a positive integer, we know that it will always result in a multiple of 3.
To expand on this, if we write out possibilities, we see groupings of: [0*1*2], [1*2*3], [2*3*4], [7*8*9], ...
Since there are 3 terms, a multiple of 3 will always be in those groupings, because multiples of 3 only have 2 integers between them. So, one of the three numbers has to be a multiple of 3.
It may seem like an exception is [0*1*2]. But 0 is a multiple of every number, including 3.