GreenlightTestPrep wrote:
If
a, b, c and
d are positive integers such that
a divided by
b equals
c with remainder
d, which of the following COULD be true?
I. a < b
II. c < d
III. b < d
A) II only
B) I and II
C) II and III
D) I and III
E) I, II and III
I. a < bIf a is less than b, then the larger number will divide into the smaller number ZERO times.
For example, 3 divided by 7 equals 0 with remainder 3.
In this example, a = 3, b = 7,
c = 0 and d = 3
Since we're told c is a positive integer, it can't be the case that
c = 0In general, if a < b, then a divided by b equals 0 with remainder a.
So, a < b is impossible, which means statement I can't be true.
II. c < dThis is possible.
For example, 7 divided by 4 equals 1 with remainder 3.
In this example, a = 7, b = 4, c = 1 and d = 3, which means c < d.
So statement II CAN be true.
III. b < dUseful property: When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < DFor example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0
So, for the given information, we can conclude that d < b, which is the OPPOSITE of what statement III is saying.
In other words, statement III can't be true.
Answer: A