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Re: Car A, B, and C participate in a car race. Car A beats car B by 45m, [#permalink]
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KarunMendiratta wrote:
We can say, (Ratio of speeds of A and B)(Ratio of speeds of B and C) = (Ratio of speeds of A and C)
\([\frac{D}{(D-45)}][\frac{D}{(D-50)}] = [\frac{D}{(D-90)}]\)
\([\frac{D}{(D-45)}] = [\frac{(D-50)}{(D-90)}]\)

Solving for D, we get D = 450

Col. A: 450
Col. B: 380

Col. A > Col. B
Hence, option A
[/quote]

I think this solution is based on assumptions that have no evidence from the question. We do not know if the racers are racing at a constant speed. In fact, we do not know any information from the question that infers a relationship that constraints the racers speeds to the total distance of the race. So the answer must be D.
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Re: Car A, B, and C participate in a car race. Car A beats car B by 45m, [#permalink]
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