GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If x = 1, then
[#permalink]
08 Mar 2023, 01:03
08 Mar 2023, 01:03
Expert Reply
1
Bookmarks
00:00
Question Stats:
65% (00:22) correct
34% (00:31) wrong based on 29 sessions
Hide Show timer Statistics
If x = – 1, then \((x^6 + x^4 + x^2) – (x^5 + x^3 + x) =\)
–6
–3
0
3
6
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE ARITHMETIC
–6
–3
0
3
6
Post A Detailed Correct Solution For The Above Questions And Get A Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE ARITHMETIC
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1055
GPA: 3.39
Re: If x = 1, then
[#permalink]
04 Apr 2023, 00:00
04 Apr 2023, 00:00
1
Expert Reply
We can solve this by substituting x = -1 in the given expression and simplifying it:
(x^6 + x^4 + x^2) - (x^5 + x^3 + x)
= [(-1)^6 + (-1)^4 + (-1)^2] - [(-1)^5 + (-1)^3 + (-1)]
= [1 + 1 + 1] - [-1 - 1 - 1]
= 3 - (-3)
= 3 + 3
= 6
Therefore, if x = -1, then (x^6+x^4+x2)–(x^5+x^3+x) = 6.
Answer: E
(x^6 + x^4 + x^2) - (x^5 + x^3 + x)
= [(-1)^6 + (-1)^4 + (-1)^2] - [(-1)^5 + (-1)^3 + (-1)]
= [1 + 1 + 1] - [-1 - 1 - 1]
= 3 - (-3)
= 3 + 3
= 6
Therefore, if x = -1, then (x^6+x^4+x2)–(x^5+x^3+x) = 6.
Answer: E
gmatclubot
Re: If x = 1, then [#permalink]
04 Apr 2023, 00:00
Moderators:
