GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2506
Given Kudos: 1053
GPA: 3.39
Re: If ab < 0, which of the following must be true?
[#permalink]
08 Apr 2023, 04:19
Based on the given information that ab < 0, where a and b are real numbers, we can deduce the following:
a < 0: This is not necessarily true. For example, if a = -2 and b = 3, then ab = (-2)(3) = -6 < 0, but a = -2 > 0.
b > 0: This is not necessarily true. For example, if a = 3 and b = -2, then ab = (3)(-2) = -6 < 0, but b = -2 < 0.
a/b < 0: This must be true. Since ab < 0, and a and b have opposite signs (one is positive and the other is negative), the quotient a/b will also have a different sign than ab. Therefore, a/b < 0 must be true.
2a - 3b > 0: This is not necessarily true. For example, if a = 1 and b = 1/3, then ab = (1)(1/3) = 1/3 > 0, but 2a - 3b = 2(1) - 3(1/3) = 2 - 1 = 1 > 0.
a + b > 0: This is not necessarily true. For example, if a = -1 and b = -2, then ab = (-1)(-2) = 2 > 0, but a + b = (-1) + (-2) = -3 < 0.
So, the only statement that must be true is a/b < 0.
Answer: C