Last visit was: 21 Nov 2024, 20:47 It is currently 21 Nov 2024, 20:47

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36341 [10]
Given Kudos: 25927
Send PM
Most Helpful Community Reply
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [8]
Given Kudos: 136
Send PM
General Discussion
avatar
Supreme Moderator
Joined: 01 Nov 2017
Posts: 371
Own Kudos [?]: 470 [2]
Given Kudos: 0
Send PM
Manager
Manager
Joined: 16 Dec 2019
Posts: 190
Own Kudos [?]: 132 [0]
Given Kudos: 59
Send PM
Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
If there are 320 workers then managers = 48 and directors = 9 Total = 377

Why not 48 mangers ? Is the question asking least number of managers possible
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36341 [1]
Given Kudos: 25927
Send PM
Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
1
Expert Reply
OE

In order to solve this multi-part Ratio problem, you must first establish a common term. As given, the number of managers appears as 3 in one ratio and as 5 in the other. The least common multiple of 3 and 5 is 15. Thus, by multiplying the first ratio by 3 and the second ratio by 3, you can make the number of managers the same, enabling you to combine the two ratios into one:

W : M = 20 : 3 = 100 : 15 and M : D = 5 : 1 = 15 : 3, so that W: M : D = 100 : 15 : 3

So, for every 3 directors, there will be 15 managers and 100 workers. Thus, a “unit” of employees is 3 + 15 + 100 = 118. From this, you see that the total number of em­ployees will need to be some integer multiple of 118. The only such number be­ tween 300 and 400 is 3 x 118, which is 334. Thus, the number of managers will be given by the same multiplier: 3x15 = 45.
Manager
Manager
Joined: 16 Dec 2019
Posts: 190
Own Kudos [?]: 132 [1]
Given Kudos: 59
Send PM
Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
1
Carcass wrote:
OE

In order to solve this multi-part Ratio problem, you must first establish a common term. As given, the number of managers appears as 3 in one ratio and as 5 in the other. The least common multiple of 3 and 5 is 15. Thus, by multiplying the first ratio by 3 and the second ratio by 3, you can make the number of managers the same, enabling you to combine the two ratios into one:

W : M = 20 : 3 = 100 : 15 and M : D = 5 : 1 = 15 : 3, so that W: M : D = 100 : 15 : 3

So, for every 3 directors, there will be 15 managers and 100 workers. Thus, a “unit” of employees is 3 + 15 + 100 = 118. From this, you see that the total number of em­ployees will need to be some integer multiple of 118. The only such number be­ tween 300 and 400 is 3 x 118, which is 334. Thus, the number of managers will be given by the same multiplier: 3x15 = 45.

Thank you I got it. I was confused actually

Posted from my mobile device
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5030
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: A company employs 20 workers for every 3 managers, and 5 [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne