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Re: Joseph went to buy at least one of each of cake, cookie [#permalink]
Expert Reply
We have the baseline that is the sum of the three amounts, one of each =21


You can add either 2 more $5 or 3 of $5 and we do have 2 ways

Or 2 more $6 and we have another way

Or you can add 1 more of $10 and you have another way

Or you can add 1 more of $10 and 1 of $5 and you have another way

The answer should be D
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Re: Joseph went to buy at least one of each of cake, cookie [#permalink]
5,6,10 can go in this order

5,18,10 (1,3,1)
10,12,10(2,2,1
15,6,10(3,1,1)
5,6,20(1,1,2)
20,6,10(4,1,1)
10,6,20(2,1,2)

these itself become 6 , so shouldn't the answer be E ?

correct me if i am wrong
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Re: Joseph went to buy at least one of each of cake, cookie [#permalink]
raghav4202 wrote:
5,6,10 can go in this order

5,18,10 (1,3,1)
10,12,10(2,2,1
15,6,10(3,1,1)
5,6,20(1,1,2)
20,6,10(4,1,1)
10,6,20(2,1,2)

these itself become 6 , so shouldn't the answer be E ?

correct me if i am wrong


i guess it's right...
i try to solve like that atleast 1 of each is require so 21$ ( 5+6+10) definitely spend then remains (30-21)&(36-21)= 9 to 15$

(10)
(5,5)
(5,6)
(5,10)
(5,5,5)
(6,6)

yeah so more than 5...

i was just hoping if someone knows simpler way.
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Re: Joseph went to buy at least one of each of cake, cookie [#permalink]
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Will see if BrushMyQuant could help us.


I saw online and the question looks like D is the answer :dontknow:
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Re: Joseph went to buy at least one of each of cake, cookie [#permalink]
1
You also counted 6 only sir.
Carcass wrote:
We have the baseline that is the sum of the three amounts, one of each =21


You can add either 2 more $5 or 3 of $5 and we do have 2 ways

Or 2 more $6 and we have another way

Or you can add 1 more of $10 and you have another way

Or you can add 1 more of $10 and 1 of $5 and you have another way

The answer should be D
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Re: Joseph went to buy at least one of each of cake, cookie [#permalink]
Expert Reply
BrushMyQuant wrote:
You also counted 6 only sir.
Carcass wrote:
We have the baseline that is the sum of the three amounts, one of each =21


You can add either 2 more $5 or 3 of $5 and we do have 2 ways

Or 2 more $6 and we have another way

Or you can add 1 more of $10 and you have another way

Or you can add 1 more of $10 and 1 of $5 and you have another way

The answer should be D



:please: :please:
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Re: Joseph went to buy at least one of each of cake, cookie [#permalink]
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