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Joined: 16 May 2014
Posts: 592
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GRE 1: Q165 V161
If x is an integer, and 169 < x^2 < 324
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06 Aug 2014, 13:47
06 Aug 2014, 13:47
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Question Stats:
45% (00:59) correct
54% (00:43) wrong based on 91 sessions
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If x is an integer, and \(169 < x^2 < 324\), which of the following is the sum of all values of x?
(A) 61
(B) 62
(C) 75
(D) 93
(E) None of the above.
(A) 61
(B) 62
(C) 75
(D) 93
(E) None of the above.
Re: GRE Math Challenge #1
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06 Aug 2014, 23:45
06 Aug 2014, 23:45
1
Correct answer is 0, Hence (E).
x = {-17,-16,-15,-14,14,15,16,17}, Sum of all values = 0
x = {-17,-16,-15,-14,14,15,16,17}, Sum of all values = 0
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Joined: 09 May 2016
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Re: GRE Math Challenge #1-x is an integer, and 169 < x^2 < 324
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20 Dec 2017, 06:21
20 Dec 2017, 06:21
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Expert Reply
soumya1989 wrote:
Level 170 question
If x is an integer, and \(169 < x^2 < 324\), which of the following is the sum of all values of x?
(A) 61
(B) 62
(C) 75
(D) 93
(E) None of the above.
If x is an integer, and \(169 < x^2 < 324\), which of the following is the sum of all values of x?
(A) 61
(B) 62
(C) 75
(D) 93
(E) None of the above.
We are given that 169 < x^2 < 324. That is, 13 < |x| < 18. If x is positive, x = 14, 15, 16, 17. If x is negative, x = -14, -15, -16, -17. We see that for every positive value of x, the opposite (or negative) is also a possibility. Thus, the sum of all values of x will be zero.
Answer: E
