GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
b and c are negative integers whereas p and q are positive odd integer
[#permalink]
06 Jul 2023, 04:17
06 Jul 2023, 04:17
Expert Reply
2
Bookmarks
00:00
Question Stats:
88% (01:52) correct
12% (02:14) wrong based on 25 sessions
Hide Show timer Statistics
b and c are negative integers whereas p and q are positive odd integers.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
Quantity A |
Quantity B |
\( c^p+b^q\) |
\(p^b-b^p\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
b and c are negative integers whereas p and q are positive odd integer
[#permalink]
07 Aug 2023, 08:51
07 Aug 2023, 08:51
1
Expert Reply
OE
Given than b and c are negative integers whereas p and q are positive odd integers.
Thus, let š = āš„ and š = āy
Quantity A
\(c^p+b^q=-x^p+(-y)^q\)
Since the base is negative and the power is odd, the result of the power will be negative
Quantity B
\(p^b-b^p=(p)^{-x}-(-y)^p=\frac{1}{p^x}-[-y^p]=\frac{1}{p^x}+y^p\)
For some positive value
Thus, Quantity A will be a negative value and Quantity B will be a positive value, hence Quantity B will definitely be larger.
Given than b and c are negative integers whereas p and q are positive odd integers.
Thus, let š = āš„ and š = āy
Quantity A
\(c^p+b^q=-x^p+(-y)^q\)
Since the base is negative and the power is odd, the result of the power will be negative
Quantity B
\(p^b-b^p=(p)^{-x}-(-y)^p=\frac{1}{p^x}-[-y^p]=\frac{1}{p^x}+y^p\)
For some positive value
Thus, Quantity A will be a negative value and Quantity B will be a positive value, hence Quantity B will definitely be larger.
Re: b and c are negative integers whereas p and q are positive odd integer
[#permalink]
15 Apr 2024, 15:40
15 Apr 2024, 15:40
1
taking values,
b = -1, c = -2 (negative integers)
p = 1, q =3 (positive odd integers)
QA= -2^1 - 1^3 , QB = 1^-1 + 1^1
QA<QB
b = -1, c = -2 (negative integers)
p = 1, q =3 (positive odd integers)
QA= -2^1 - 1^3 , QB = 1^-1 + 1^1
QA<QB
