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b and c are negative integers whereas p and q are positive odd integer
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06 Jul 2023, 04:17
06 Jul 2023, 04:17
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18% (02:14) wrong based on 16 sessions
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b and c are negative integers whereas p and q are positive odd integers.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
_________________
Quantity A |
Quantity B |
\( c^p+b^q\) |
\(p^b-b^p\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Post A Detailed Correct Solution For The Above Questions And Get Kudos.
Question From Our Project: Free GRE Prep Club Tests in Exchange for 20 Kudos
\(\Longrightarrow\) GRE - Quant Daily Topic-wise Challenge
\(\Longrightarrow\) GRE NUMBER PROPERTIES
_________________
b and c are negative integers whereas p and q are positive odd integer
[#permalink]
07 Aug 2023, 08:51
07 Aug 2023, 08:51
1
Expert Reply
OE
Given than b and c are negative integers whereas p and q are positive odd integers.
Thus, let š = āš„ and š = āy
Quantity A
\(c^p+b^q=-x^p+(-y)^q\)
Since the base is negative and the power is odd, the result of the power will be negative
Quantity B
\(p^b-b^p=(p)^{-x}-(-y)^p=\frac{1}{p^x}-[-y^p]=\frac{1}{p^x}+y^p\)
For some positive value
Thus, Quantity A will be a negative value and Quantity B will be a positive value, hence Quantity B will definitely be larger.
_________________
Given than b and c are negative integers whereas p and q are positive odd integers.
Thus, let š = āš„ and š = āy
Quantity A
\(c^p+b^q=-x^p+(-y)^q\)
Since the base is negative and the power is odd, the result of the power will be negative
Quantity B
\(p^b-b^p=(p)^{-x}-(-y)^p=\frac{1}{p^x}-[-y^p]=\frac{1}{p^x}+y^p\)
For some positive value
Thus, Quantity A will be a negative value and Quantity B will be a positive value, hence Quantity B will definitely be larger.
_________________
gmatclubot
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