OE


Given than b and c are negative integers whereas p and q are positive odd integers.
Thus, let 𝑏 = −𝑥 and 𝑐 = −y

Quantity A

\(c^p+b^q=-x^p+(-y)^q\)

Since the base is negative and the power is odd, the result of the power will be negative

Quantity B

\(p^b-b^p=(p)^{-x}-(-y)^p=\frac{1}{p^x}-[-y^p]=\frac{1}{p^x}+y^p\)


For some positive value

Thus, Quantity A will be a negative value and Quantity B will be a positive value, hence Quantity B will definitely be larger.
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