sandy wrote:
A container is \(\frac{4}{5}\) full. After 3 liters of its contents are poured out, the container is \(\frac{3}{4}\) full. How many liters would need to be poured back in to refill the container?
Let C = capacity of the container
We can write: (original volume of liquid) - 3 liters = (new volume of liquid)
Rewrite as: (4/5 of C) - 3 = (3/4 of C)
Or...: 4C/5 - 3 = 3C/4
Rearrange to get: 4C/5 - 3C/4 = 3
Rewrite with common denominators: 16C/20 - 15C/20 = 3
Simplify: C/20 = 3
Solve: C = 60
In other words, the container's capacity is
60 litersIf the container is 3/4 full, then the volume of liquid = 3/4 of
60 liters = 45 liters
So, we must add 15 more liters to fill the container.
Answer:
Cheers,
Brent