Carcass wrote:
In trapezium ABCD, AB || CD and AC = BD. If area of the trapezium is 60 sq units and height of the trapezium is 10 units, what is the length of diagonal BD?
A. 10 units
B. \(\sqrt{116}\) unites
C. \(5\sqrt{ 5}\) units
D. \(\sqrt{136}\) units
E. 12 units
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GRE GEOMETRYIt is given that it is a trapeziam but the parallel sides are equal to each other.
This makes the sides joining both the parallel side to be perpendicular (90 degrees).
This makes it a recatangle.
Area of rectangle lxb = 60 (given)
height =10 (given).
Therefore considering the height as the length of the rectangle we get b as 6.
To get the length of the diagonal we have to apply pythagoras theorem.
diagonal^2 = 10^2 + 6^2
therefore diagonal = \(\sqrt{136}\)
option D)