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A 2-foot by 2-foot by 2-foot solid cube is cut into 2-inch b [#permalink]
1
The only shortcut here is to cancel by 2. Hence total surface area of small solids is \( 40*(6*6*3)\). The double reduced area of a cube is \(3*12*12\). The required ratio is \(\frac{40*6*6*3}{3*12*12}\)=\(\frac{40}{4}\)=\(10:1\)

Answer is E
sandy wrote:
A 2-foot by 2-foot by 2-foot solid cube is cut into 2-inch by 2-inch by 4-inch rectangular solids. What is the ratio of the total surface area of all the resulting smaller rectangular solids to the surface area of the original cube? (1 foot = 12 inches)

(A) 2 : 1
(B) 4 : 1
(C) 5 : 1
(D) 8 : 1
(E) 10 : 1
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Re: A 2-foot by 2-foot by 2-foot solid cube is cut into 2-inch b [#permalink]
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Re: A 2-foot by 2-foot by 2-foot solid cube is cut into 2-inch b [#permalink]
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