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8x is an integer, where 0 < x < 1.
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25 Sep 2023, 23:05
25 Sep 2023, 23:05
Expert Reply
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Question Stats:
70% (01:20) correct
30% (02:09) wrong based on 20 sessions
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8x is an integer, where 0 < x < 1.
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The tenth digit in the decimal representation of x |
0 |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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GRE Geometry Formulas
GRE - Math Book
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Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
8x is an integer, where 0 < x < 1.
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14 Oct 2023, 09:14
14 Oct 2023, 09:14
Expert Reply
8x=Integer
x=Integer/8 and the integer must be <8
Suppose is 1/8=0.125
=> The tenth digit is ‘1’
Since for the smallest possible value of x, the tenth digit is ‘1’, the tenth digit will always be greater than or equal to ‘1’ for all higher values of x
Other possible values of x are x =1/2= 0.50 & x =1/4= 0.25. We see that the tenth digit is rather greater than ‘1’.
A is the answer
x=Integer/8 and the integer must be <8
Suppose is 1/8=0.125
=> The tenth digit is ‘1’
Since for the smallest possible value of x, the tenth digit is ‘1’, the tenth digit will always be greater than or equal to ‘1’ for all higher values of x
Other possible values of x are x =1/2= 0.50 & x =1/4= 0.25. We see that the tenth digit is rather greater than ‘1’.
A is the answer
Re: 8x is an integer, where 0 < x < 1.
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08 Nov 2023, 13:16
08 Nov 2023, 13:16
Carcass wrote:
8x=Integer
x=Integer/8 and the integer must be <8
Suppose is 1/8=0.125
=> The tenth digit is ‘1’
Since for the smallest possible value of x, the tenth digit is ‘1’, the tenth digit will always be greater than or equal to ‘1’ for all higher values of x
Other possible values of x are x =1/2= 0.50 & x =1/4= 0.25. We see that the tenth digit is rather greater than ‘1’.
A is the answer
x=Integer/8 and the integer must be <8
Suppose is 1/8=0.125
=> The tenth digit is ‘1’
Since for the smallest possible value of x, the tenth digit is ‘1’, the tenth digit will always be greater than or equal to ‘1’ for all higher values of x
Other possible values of x are x =1/2= 0.50 & x =1/4= 0.25. We see that the tenth digit is rather greater than ‘1’.
A is the answer
Carcass,
What about x=1/2, would that not give a value of 4, in which case the tens digit is "0"?
