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Tina, Ed, and Lauren agree to share the cost of a gift
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09 May 2015, 11:32
09 May 2015, 11:32
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Question Stats:
83% (01:15) correct
16% (02:01) wrong based on 128 sessions
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Tina, Ed, and Lauren agree to share the cost of a gift and to make their contributions in proportion to their ages. Ed’s age is \(\frac{1}{2}\) of Tina’s age, and Lauren’s age is \(\frac{1}{3}\) of Ed’s age. If Lauren’s share of the cost is $ 2.50, what is the cost of the gift?
(A) $25
(B) $20
(C) $15
(D) $12
(E) $10
Kudos for the right answer and explanation
(A) $25
(B) $20
(C) $15
(D) $12
(E) $10
Kudos for the right answer and explanation
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Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: GRE Math Challenge #91
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16 May 2015, 08:55
16 May 2015, 08:55
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sandy wrote:
Tina, Ed, and Lauren agree to share the cost of a gift and to make their contributions in proportion to their ages. Ed’s age is ½ of Tina’s age, and Lauren’s age is 1/3 of Ed’s age. If Lauren’s share of the cost is $ 2.50, what is the cost of the gift?
(A) $25
(B) $20
(C) $15
(D) $12
(E) $10
(A) $25
(B) $20
(C) $15
(D) $12
(E) $10
To get a better idea of the age proportions, let's assign some values that meet the given conditions.
Lauren’s age is 1/3 of Ed’s age
So, let Ed's age = 3 years
This means that Lauren’s age = 1 year
Ed’s age is ½ of Tina’s age
If Ed's age = 3 years, then Tina’s age = 6
So, the proportion (Ed's age) : (Tina’s age) : (Lauren’s age) = 3 : 6 : 1
3 + 6 + 1 = 10
So, Lauren's contribution = 1/10 of the TOTAL cost
If Lauren’s share of the cost is $ 2.50, then the TOTAL cost = (10)($2.50) = $25
Answer:
Show: ::
A
Cheers,
Brent
Re: Tina, Ed, and Lauren agree to share the cost of a gift
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11 Dec 2019, 10:19
11 Dec 2019, 10:19
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Bump for further discussion
