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The product of positive integers b and c is 60. If b is doub
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02 Oct 2017, 22:27
02 Oct 2017, 22:27
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Question Stats:
72% (00:52) correct
27% (02:43) wrong based on 29 sessions
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The product of positive integers b and c is 60. If b is doubled, then c must decrease by what percent so that the product of the two will still equal 60?
(A) 10
(B) 25
(C) 50
(D) 200
(E) Cannot be determined from information given.
Kudos for correct solution.
(A) 10
(B) 25
(C) 50
(D) 200
(E) Cannot be determined from information given.
Kudos for correct solution.
Re: The product of positive integers b and c is 60. If b is doub
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03 Oct 2017, 02:49
03 Oct 2017, 02:49
We know that \(bc = 60\), thus if b is doubled, we get \(2bc' = 60\), where c' is the new value of c. It is easy to see that \(c' = \frac{c}{2}\) in order to keep the product equal to 60. The percentage decrease is computed as \(\frac{\frac{c}{2}-c}{c}*100 = 50%\).
Answer C
Answer C
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Re: The product of positive integers b and c is 60. If b is doub
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09 Dec 2023, 02:31
09 Dec 2023, 02:31
1
The product of positive integers b and c is 60
=> b*c= 60
If b is doubled, then c must decrease by what percent so that the product of the two will still equal 60?
=> 2b * \(c_{new}\) = 60 = bc
=> \(c_{new}\) = \(\frac{c}{2}\)
=> c became 50% of its previous value
=> c decreased by 50%
So, Answer will be C
Hope it helps!
=> b*c= 60
If b is doubled, then c must decrease by what percent so that the product of the two will still equal 60?
=> 2b * \(c_{new}\) = 60 = bc
=> \(c_{new}\) = \(\frac{c}{2}\)
=> c became 50% of its previous value
=> c decreased by 50%
So, Answer will be C
Hope it helps!
