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If f(x) = x2 - 9, what is the value of f(3)?
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24 Feb 2022, 07:00
24 Feb 2022, 07:00
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If \(f(x) =\frac{ x^2 - 9}{x-3}\), what is the value of f(3)?
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
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Re: If f(x) = x2 - 9, what is the value of f(3)?
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04 Mar 2022, 23:49
04 Mar 2022, 23:49
1
Carcass wrote:
If \(f(x) =\frac{ x^2 - 9}{x-3}\), what is the value of f(3)?
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
(A) -6
(B) 0
(C) 1
(D) 6
(E) Undefined
Plug x = 3
f(3) = \(\frac{3^2 - 9}{0}\)
Since, the denominator is 0, f(3) is undefined
Hence, option E
Suggestion: DO NOT factorize the function and then solve
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If f(x) = x2 - 9, what is the value of f(3)?
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07 Aug 2022, 10:25
07 Aug 2022, 10:25
Given that \(f(x) =\frac{ x^2 - 9}{x-3}\) and we need to find the value of f(3)
To find f(3) we need to compare what is inside the bracket in f(3) and f(x)
=> We need to substitute x with 3 in \(f(x) =\frac{ x^2 - 9}{x-3}\) to get the value of f(3)
=> \(f(3) =\frac{ 3^2 - 9}{3-3}\) = \(\frac{9-9}{0}\) = \(\frac{0}{0}\) = Undefined ( as anything divided by 0 is Undefined)
So, Answer will be E
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
To find f(3) we need to compare what is inside the bracket in f(3) and f(x)
=> We need to substitute x with 3 in \(f(x) =\frac{ x^2 - 9}{x-3}\) to get the value of f(3)
=> \(f(3) =\frac{ 3^2 - 9}{3-3}\) = \(\frac{9-9}{0}\) = \(\frac{0}{0}\) = Undefined ( as anything divided by 0 is Undefined)
So, Answer will be E
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
