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Re: If a triangle has sides measuring 3 inches and 12 inches, which of th
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23 Dec 2022, 05:00
Expert Reply
Any side x of a triangle must be greater than the difference between the lengths of the two other sides, and less than the sum of the two other sides. Therefore, 7 < x < 17. Only 17.5 inches is outside this range.
Re: If a triangle has sides measuring 3 inches and 12 inches, which of th
[#permalink]
21 Jan 2023, 19:39
2
Carcass wrote:
Any side x of a triangle must be greater than the difference between the lengths of the two other sides, and less than the sum of the two other sides. Therefore, 7 < x < 17. Only 17.5 inches is outside this range.
This should be 12+ 3 & 12-3. So, 9<x<15.... how are you getting 7 and 17?
Re: If a triangle has sides measuring 3 inches and 12 inches, which of th
[#permalink]
22 Jan 2023, 00:54
Expert Reply
OE
Any side x of a triangle must be greater than the difference between the lengths of the two other sides, and less than the sum of the two other sides. In this case, the third side must be between (12 - 5) = 7 inches, and (12 + 5) = 17 inches. Therefore, 7 < x < 17. Only 17.5 inches is outside this range.
Re: If a triangle has sides measuring 3 inches and 12 inches, which of th
[#permalink]
28 Dec 2023, 14:45
1
Carcass wrote:
OE
Any side x of a triangle must be greater than the difference between the lengths of the two other sides, and less than the sum of the two other sides. In this case, the third side must be between (12 - 5) = 7 inches, and (12 + 5) = 17 inches. Therefore, 7 < x < 17. Only 17.5 inches is outside this range.
The question says the side is length 3, not length 5.