GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If the average (arithmetic mean) of five distinct positive integers is
[#permalink]
25 Jan 2024, 02:05
25 Jan 2024, 02:05
Expert Reply
1
Bookmarks
00:00
Question Stats:
50% (02:13) correct
50% (01:57) wrong based on 4 sessions
Hide Show timer Statistics
If the average (arithmetic mean) of five distinct positive integers is 10, what is the least possible value of the greatest of the five integers?
(A) 11
(B) 12
(C) 24
(D) 40
(E) 46
(A) 11
(B) 12
(C) 24
(D) 40
(E) 46
Part of the project: GRE-Problem Solving Practice Questions Special Edition {PS,MAC, & NE} - Gain 20 Kudos & Get FREE Access to GRE Prep Club TESTS
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Free Materials for the GRE General Exam - Where to get it!!
GRE Geometry Formulas
GRE - Math Book
Manager
Joined: 11 Nov 2023
Posts: 228
Given Kudos: 78
WE:Business Development (Advertising and PR)
If the average (arithmetic mean) of five distinct positive integers is
[#permalink]
26 Jan 2024, 16:46
26 Jan 2024, 16:46
1
Let x = the smallest integer of the set.
Since the numbers are all distinct integers:
the LEAST possible value for the 2nd integer = x + 1
the LEAST possible value for the 3rd integer = 2nd integer + 1 = x + 2
the LEAST possible value for the 4th integer = 3rd integer + 1 = x + 3
the LEAST possible value for the 5th integer = 4th integer + 1 = x + 4
The average of the five integers =
\(\frac{x+x+1+x+2+x+3+x+4}{5} = \frac{5x+10}{5} = 10\)
\(5x + 10 = 50\)
\(5x = 40\)
\(x = 8\)
The greatest of the five integers =
\(x + 4 = 8 + 4 =12\)
Since the numbers are all distinct integers:
the LEAST possible value for the 2nd integer = x + 1
the LEAST possible value for the 3rd integer = 2nd integer + 1 = x + 2
the LEAST possible value for the 4th integer = 3rd integer + 1 = x + 3
the LEAST possible value for the 5th integer = 4th integer + 1 = x + 4
The average of the five integers =
\(\frac{x+x+1+x+2+x+3+x+4}{5} = \frac{5x+10}{5} = 10\)
\(5x + 10 = 50\)
\(5x = 40\)
\(x = 8\)
The greatest of the five integers =
\(x + 4 = 8 + 4 =12\)
gmatclubot
If the average (arithmetic mean) of five distinct positive integers is [#permalink]
26 Jan 2024, 16:46
Moderators:
