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If the average (arithmetic mean) of five distinct positive integers is
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26 Jan 2024, 16:46
Let x = the smallest integer of the set.
Since the numbers are all distinct integers:
the LEAST possible value for the 2nd integer = x + 1
the LEAST possible value for the 3rd integer = 2nd integer + 1 = x + 2
the LEAST possible value for the 4th integer = 3rd integer + 1 = x + 3
the LEAST possible value for the 5th integer = 4th integer + 1 = x + 4
The average of the five integers =
\(\frac{x+x+1+x+2+x+3+x+4}{5} = \frac{5x+10}{5} = 10\)
\(5x + 10 = 50\)
\(5x = 40\)
\(x = 8\)
The greatest of the five integers =
\(x + 4 = 8 + 4 =12\)