Carcass wrote:
If \(\frac{3x}{2}=\frac{5}{7y}\) and \(\frac{3y}{5}=\frac{a}{x}\), what is the value of \(a\) ?
Kudos for the right answer and explanation
GIVEN: \(\frac{3x}{2}=\frac{5}{7y}\)
Cross multiply to get: \((3x)(7y) = (2)(5)\)
Simplify: \(21xy = 20\)
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GIVEN: \(\frac{3y}{5}=\frac{a}{x}\)
Cross multiply to get: \((x)(3y) = (5)(a)\)
Simplify: \(3xy =5a\)
Multiply both sides by 7 to get: \(21xy =35a\)
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At this point we know the following:
\(21xy = 20\)
\(21xy =35a\)
Since both equations are set equal to \(21xy\), we can conclude that: \(35a =10\)
Divide both sides by 35 to get: \(a = \frac{10}{35} = \frac{2}{7}\)
Answer: \(\frac{2}{7}\)
Cheers,
Brent