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A, B, C are three consecutive positive integers (A>B>C). What is the v
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24 May 2021, 03:55
24 May 2021, 03:55
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A, B, C are three consecutive positive integers (A>B>C). What is the value of the expression 2A +B +3C?
A. 6A+7.
B. 5A+1.
C. 5A-1.
D. 6A-5.
E. 6A-7.
A. 6A+7.
B. 5A+1.
C. 5A-1.
D. 6A-5.
E. 6A-7.
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Re: A, B, C are three consecutive positive integers (A>B>C). What is the v
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24 May 2021, 05:41
24 May 2021, 05:41
1
Carcass wrote:
A, B, C are three consecutive positive integers (A>B>C). What is the value of the expression 2A +B +3C?
A. 6A + 7
B. 5A + 1
C. 5A - 1
D. 6A - 5
E. 6A - 7
A. 6A + 7
B. 5A + 1
C. 5A - 1
D. 6A - 5
E. 6A - 7
Here's another approach:
Let the three consecutive positive integers be 1, 2 and 3
That is, A = 3, B = 2, C = 1
What is the value of the expression 2A +B +3C?
Well, if A = 3, B = 2, C = 1, then 2A +B +3C = 2(3) +2 +3(1) = 11
So, when A = 3, we find that A +B +3C = 11
Now test the answer choices, to see which one yields an output of 11, when A = 3
A. 6(3) + 7 = 25 ELIMINATE
B. 5(3) + 1 = 16 ELIMINATE
C. 5(3) - 1 = 14 ELIMINATE
D. 6(3) - 5 = 13 ELIMINATE
E. 6(3) - 7 = 11 KEEP
Answer:
Show: ::
E
Re: A, B, C are three consecutive positive integers (A>B>C). What is the v
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25 Feb 2024, 19:02
25 Feb 2024, 19:02
1
A, B, C are consecutive positive integers such that A>B>C
We can therefore rewrite A, B and C as
A = A
B = A-1
C= A-2
Now
2A + B + 3C = 2A + A-1 + 3(A-2) = 2A + A-1 + 3A-6 = 6A-7.
The answer is E
We can therefore rewrite A, B and C as
A = A
B = A-1
C= A-2
Now
2A + B + 3C = 2A + A-1 + 3(A-2) = 2A + A-1 + 3A-6 = 6A-7.
The answer is E
