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If f(x) = x2 – 1, what is the value of f(y) + f(–1)?
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25 Jul 2018, 17:12
25 Jul 2018, 17:12
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Expert Reply
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Question Stats:
95% (00:27) correct
4% (00:56) wrong based on 65 sessions
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If \(f(x) = x^2 - 1\), what is the value of \(f(y) + f(-1)\)?
(A) \(y^2 - 1\)
(B) \(y^2\)
(C) \(y^2 + 1\)
(D) \(y^2 - 2y\)
(E) \(y^2 - 2y - 1\)
(A) \(y^2 - 1\)
(B) \(y^2\)
(C) \(y^2 + 1\)
(D) \(y^2 - 2y\)
(E) \(y^2 - 2y - 1\)
Re: If f(x) = x2 – 1, what is the value of f(y) + f(–1)?
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31 Jul 2018, 14:22
31 Jul 2018, 14:22
Expert Reply
Explanation
The question requires plugging y into the function, then plugging –1 into the function, then summing the two results:
\(f(y) = y^2 - 1\)
\(f(-1) = (-1)^2 - 1\)
\(f(-1) = 0\)
Thus, \(f(y) + f(-1) = y^2 - 1 + 0 = y^2 - 1\).
The question requires plugging y into the function, then plugging –1 into the function, then summing the two results:
\(f(y) = y^2 - 1\)
\(f(-1) = (-1)^2 - 1\)
\(f(-1) = 0\)
Thus, \(f(y) + f(-1) = y^2 - 1 + 0 = y^2 - 1\).
Re: If f(x) = x2 1, what is the value of f(y) + f(1)?
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01 Apr 2024, 00:37
01 Apr 2024, 00:37
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
