GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If values of the 30th and 40th percentiles values are 12 and 16..
[#permalink]
13 Mar 2022, 11:33
13 Mar 2022, 11:33
1
4
Bookmarks
00:00
Question Stats:
49% (01:39) correct
49% (01:26) wrong based on 28 sessions
Hide Show timer Statistics
If values of the 30th and 40th percentiles values are 12 and 16 of the distribution of X. and the random variable X is normally distributed.
Options:
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\) The value at the 35th Percentile |
\(14\) |
Options:
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Re: If values of the 30th and 40th percentiles values are 12 and 16..
[#permalink]
13 Mar 2022, 11:57
13 Mar 2022, 11:57
1
Expert Reply
The value 14 is exactly at halfway between 12 and 16. Since the normal curve is increasing in that interval (i.e., approaching 50th percentile), the area between 14 and 16 will be greater than the area between 12 and 14. In other words, more values are distributed around the mean (i.e., 50th percentile). Since the value at the 35th percentile should divide the area between 30th and 40th percentiles in half, the value here will be closer to 16 than 12. Hence, the value at 35th percentile will be greater than 14.
Answer: A
Answer: A
Re: If values of the 30th and 40th percentiles values are 12 and 16..
[#permalink]
14 Jun 2024, 06:03
14 Jun 2024, 06:03
someone explain in easy way please, i did not understand
