IlCreatore wrote:
Fine, the error in the formula completely drove me out way.
Just a question: I am not sure I have understood your final line "= 8 decimal point (since 641 >100)". I would have said that
6411011=164∗10−11, thus we have to move the point by 11 places behind and given that three places are numbers different from zero, there are 8 zeros before six, 11-3 = 8
This is because 641>100 and it is divisible by 100, so we need not account for that
we can leave the 3 digit because it will be greater than 100.
For example if we had
6∗10−11 = 10 decimal point before nonzero ,
64∗10−11 = 9 decimal point before nonzero
You can try that on calculator