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Re: If x^5>x^3
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09 May 2024, 09:16
I. x > 0
If x is greater than 1 (which is greater than 0), x5 will be greater than x3. Thus, (I) could be true.
E.g., if x = 2, x5 = 32 and x3 = 8 ---> 32 > 8
II. x < 0
If x is less than 0 but greater than -1, x5 will be greater than x3. Thus, (II) could be true.
E.g., if x = -0.5, x5 = -0.03125 and x3 = -0.125 ---> -0.03125 > -0.125
III. x < -1
If x is less than -1, x5 will always be less than x3. Thus, (III) cannot be true.
E.g., if x = -2, x5 = -32 and x3 = -8 ---> -32 < -8