Manager
Joined: 11 Nov 2023
Posts: 196
Given Kudos: 76
WE:Business Development (Advertising and PR)
Re: If x^5>x^3
[#permalink]
09 May 2024, 09:16
I. x > 0
If x is greater than 1 (which is greater than 0), \(x^5\) will be greater than \(x^3\). Thus, (I) could be true.
E.g., if x = 2, \(x^5\) = 32 and \(x^3\) = 8 ---> 32 > 8
II. x < 0
If x is less than 0 but greater than -1, \(x^5\) will be greater than \(x^3\). Thus, (II) could be true.
E.g., if x = -0.5, \(x^5\) = -0.03125 and \(x^3\) = -0.125 ---> -0.03125 > -0.125
III. x < -1
If x is less than -1, \(x^5\) will always be less than \(x^3\). Thus, (III) cannot be true.
E.g., if x = -2, \(x^5\) = -32 and \(x^3\) = -8 ---> -32 < -8