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A right angled triangle has base 1 unit and height of triangle is equa
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10 May 2023, 04:59
10 May 2023, 04:59
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A right angled triangle has base 1 unit and height of triangle is equal to the diagnonal of the square of side 2 units. What is the value of perimeter, to the closest integer, of the triangle?
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Re: A right angled triangle has base 1 unit and height of triangle is equa
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27 May 2023, 23:25
27 May 2023, 23:25
Expert Reply
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GRE triangles (4).jpg [ 21.79 KiB | Viewed 1905 times ]
We are given that the height of the triangle ABC = Diagonal of the square with side 2
units.
From the square, PR = h = 2√2 units (using Pythagoras theorem)
So, In triangle ABC, h = 2√2 units
By using Pythagoras theorem,
AC^2 = AB^2 + BC^2= (2√2))^2+ 1^2
AC^2 = 8 + 1 = 9
AC = 3 units.
So, the perimeter of the triangle ABC = 3 + 1 + 2√2 = 4 + 2√2 = 6.82 = 7 units (rounded off to nearest integer)
Ans. (7)
Attachment:
GRE triangles (4).jpg [ 21.79 KiB | Viewed 1905 times ]
We are given that the height of the triangle ABC = Diagonal of the square with side 2
units.
From the square, PR = h = 2√2 units (using Pythagoras theorem)
So, In triangle ABC, h = 2√2 units
By using Pythagoras theorem,
AC^2 = AB^2 + BC^2= (2√2))^2+ 1^2
AC^2 = 8 + 1 = 9
AC = 3 units.
So, the perimeter of the triangle ABC = 3 + 1 + 2√2 = 4 + 2√2 = 6.82 = 7 units (rounded off to nearest integer)
Ans. (7)
Re: A right angled triangle has base 1 unit and height of triangle is equa
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26 Oct 2024, 18:17
26 Oct 2024, 18:17
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