We know that the probabilities of selecting a number out of 4 different numbers are $$P_1, P_2, P_3$ \& $\mathrm{P}_4$$ for four numbers; we need to check that which of the given values could be the individual values of the four probabilities.

Since there are 4 numbers in the set and $$P_1, P_2, P_3 \& P_4$$ are the probabilities of those four numbers, the sum of their probabilities must be equal to 1 (The chances of selection of any one the four numbers i.e. $$\mathrm{P}_1, \mathrm{P}_2, \mathrm{P}_3 \& \mathrm{P}_4$$ in the set of 4 numbers only is $$100 \%=1$$ ).

The only option giving the sum of the probabilities 1 is option (C).
Hence the answer is (C).