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The probabilities of selecting a number out of four different numbers
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17 Nov 2024, 15:11
17 Nov 2024, 15:11
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Question Stats:
33% (01:05) correct
66% (01:18) wrong based on 3 sessions
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The probabilities of selecting a number out of four different numbers are \(P_1, P_2, P_3, P_4\) for the four numbers. Which of the following could be the individual values of the four probabilities?
A. \(P_1=0.4; P_2=0.3; P_3=0.2; P_4=0.2\)
B. \(P_1=0.4; P_2=0.25; P_3=0.2; P_4=0.25\)
C. \(P_1=0.2; P_2=0.25; P_3=0.4; P_4=0.15\)
D. \(P_1=0.3; P_2=0.2; P_3=0.4; P_4=0.2\)
E. \(P_1=0.5; P_2=0.3; P_3=0.2; P_4=0.1\)
A. \(P_1=0.4; P_2=0.3; P_3=0.2; P_4=0.2\)
B. \(P_1=0.4; P_2=0.25; P_3=0.2; P_4=0.25\)
C. \(P_1=0.2; P_2=0.25; P_3=0.4; P_4=0.15\)
D. \(P_1=0.3; P_2=0.2; P_3=0.4; P_4=0.2\)
E. \(P_1=0.5; P_2=0.3; P_3=0.2; P_4=0.1\)
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Re: The probabilities of selecting a number out of four different numbers
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20 Dec 2024, 11:16
20 Dec 2024, 11:16
Expert Reply
We know that the probabilities of selecting a number out of 4 different numbers are $\(P_1, P_2, P_3$ \& $\mathrm{P}_4\)$ for four numbers; we need to check that which of the given values could be the individual values of the four probabilities.
Since there are 4 numbers in the set and $\(P_1, P_2, P_3 \& P_4\)$ are the probabilities of those four numbers, the sum of their probabilities must be equal to 1 (The chances of selection of any one the four numbers i.e. $\(\mathrm{P}_1, \mathrm{P}_2, \mathrm{P}_3 \& \mathrm{P}_4\)$ in the set of 4 numbers only is $\(100 \%=1\)$ ).
The only option giving the sum of the probabilities 1 is option (C).
Hence the answer is (C).
Since there are 4 numbers in the set and $\(P_1, P_2, P_3 \& P_4\)$ are the probabilities of those four numbers, the sum of their probabilities must be equal to 1 (The chances of selection of any one the four numbers i.e. $\(\mathrm{P}_1, \mathrm{P}_2, \mathrm{P}_3 \& \mathrm{P}_4\)$ in the set of 4 numbers only is $\(100 \%=1\)$ ).
The only option giving the sum of the probabilities 1 is option (C).
Hence the answer is (C).
gmatclubot
Re: The probabilities of selecting a number out of four different numbers [#permalink]
20 Dec 2024, 11:16
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