We need to check from the options that for which choice the product of the three numbers is less than each of the numbers of the list


(A) The three numbers are $\(\frac{1}{3}=0.33, \frac{1}{4}=0.25 \& \frac{3}{4}=0.75\)$ whereas their product is $\(\frac{1}{3} \times \frac{1}{4} \times \frac{3}{4}=\frac{1}{16}=0.0625\)$ which is clearly less than each of the three numbers

(B) The three numbers are $\(-3,4 \& 9\)$ and their product is $\(-3 \times 4 \times 9=-108\)$ which is clearly less than each of the three numbers $\(-3,4 \& 9\)$

(C) The three numbers are $\(-\frac{2}{3}=-0.666,3 \& \frac{3}{4}=0.75\)$ and their product is $\(-\frac{2}{3} \times 3 \times \frac{3}{4}=-\frac{3}{2}=-1.5\)$ which is less than each of the three given numbers.

(D) The three numbers are $\(-3,9 \&-1\)$, whose product is $\(-3 \times 9 \times-1=27\)$ which is greater than each of the three given numbers.

Hence options (A), (B) \& (C) satisfy the condition.