We know that the slope of a line, in the intercept form, is $$-\frac{(y-\text { int ercept })}{(x-\text { int ercept })}$$, so if a line has slope $$\frac{2}{3}$$, we get the $$\frac{(y-\text { intercept })}{(x-\text { intercept })}=-\frac{2}{3}$$ which implies $$y$$-intercept $$\& x-$$ intercept must be of opposite sign.

Now, the value of ( $$y$$-intercept, $$x$$ - intercept) can be $$(-2,3)$$ or $$(2,-3)$$, so we can have either of them greater. So, $$x$$-intercept may be greater than $$y$$-intercept or vice versa.

Also if $$y$$ - intercept is negative, the x -intercept must be positive, so comes greater.
Hence options A, B, C, D all may be true, so are correct.