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Antonia drove half of her journey to her destination at an average spe
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03 Jan 2025, 01:40
03 Jan 2025, 01:40
Expert Reply
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Question Stats:
83% (02:21) correct
16% (03:24) wrong based on 12 sessions
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Antonia drove half of her journey to her destination at an average speed of $\(35 \mathrm{miles} / \mathrm{hour}\)$ for 12 hours. If she has to reach her destination in $\(T\)$ hours, which of the following should be her average speed for rest of her journey?
(A) $\(\frac{(35)(12)}{(T-12)}\)$
(B) $\(\frac{35}{T-12}\)$
(C) $\(\frac{12}{T-12}\)$
(D) $\(\frac{35}{12(T-12)}\)$
(E) $\(\frac{T-12}{(12)(35)}\)$
(A) $\(\frac{(35)(12)}{(T-12)}\)$
(B) $\(\frac{35}{T-12}\)$
(C) $\(\frac{12}{T-12}\)$
(D) $\(\frac{35}{12(T-12)}\)$
(E) $\(\frac{T-12}{(12)(35)}\)$
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Antonia drove half of her journey to her destination at an average spe
[#permalink]
09 Feb 2025, 04:55
09 Feb 2025, 04:55
Expert Reply
If half of the journey is travelled at an average speed of 35 miles $/$ hour for 12 hour, the distance of the half of the journey is \(Speed $\times$ Time $=35 \times 12\)$ miles
Since the entire journey is to be covered in a total time of T hours, the time left for the seconds half of the journey is $\((T-12)\)$ hours
Finally the speed at which Antonia should cover the second half of the journey to reach on time would be $\(\frac{ Remaining distance }{Remaining time }=\)\(\frac{35 \times 12}{(\mathrm{~T}-12)}\)$ miles / hour
Hence the answer is (A).
Since the entire journey is to be covered in a total time of T hours, the time left for the seconds half of the journey is $\((T-12)\)$ hours
Finally the speed at which Antonia should cover the second half of the journey to reach on time would be $\(\frac{ Remaining distance }{Remaining time }=\)\(\frac{35 \times 12}{(\mathrm{~T}-12)}\)$ miles / hour
Hence the answer is (A).
gmatclubot
Antonia drove half of her journey to her destination at an average spe [#permalink]
09 Feb 2025, 04:55
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